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0=5-0.15x+0.001x^2
We move all terms to the left:
0-(5-0.15x+0.001x^2)=0
We add all the numbers together, and all the variables
-(5-0.15x+0.001x^2)=0
We get rid of parentheses
-0.001x^2+0.15x-5=0
a = -0.001; b = 0.15; c = -5;
Δ = b2-4ac
Δ = 0.152-4·(-0.001)·(-5)
Δ = 0.0025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.15)-\sqrt{0.0025}}{2*-0.001}=\frac{-0.15-\sqrt{0.0025}}{-0.002} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.15)+\sqrt{0.0025}}{2*-0.001}=\frac{-0.15+\sqrt{0.0025}}{-0.002} $
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